Greek player rose from one blind in 4-max and won the WSOP bracelet

Aristeidis Moschonas poker​It’s time for high-profile comebacks at the WSOP 2019. In the $600 buy-in tournament in 4-max, Greek poker player Aristeidis Moschonas had less than one blind left and many people would have already packed the suitcase home if they had been in his shoes.

«I was down to half a big blind after the first four levels. I doubled up four times, and that’s it», – said the winner.

After Moschonas doubled up four times, he managed to establish his game and get to the heads-up. In the final, American player Dan Matsuzuki was his opponent, but Aristeidis found an appropriate game approach which allowed him to beat Dan.

Read also: Phil Ivey got his first cash at WSOP 2019

Speaking to journalists, the winner reported that his basic discipline is PLO, but he sometimes also plays No-Limit Hold'em events. This gives him an advantage over rivals in mixed tournaments since he is a broad expert in different styles of play.

Poker player Aristeidis Moschonas

WSOP 2019: $600 Mixed NLH/PLO Deepstack final table results

  1. Aristeidis Moschonas (Greece) – $194 700
  2. Dan Matsuzuki (USA) – $120 300
  3. Raghav Bansal (India) – $88 000
  4. Rainer Kempe (Germany) – $65 400
  5. Ashish Ahuja (India) – $48 900
  6. Stephen Ma (USA) – $36 800
  7. Adam Lamphere (USA) – $28 000
  8. Daniel Moravec (USA) – $21 400
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